Line Integral computation on the TI89 using Calculus Made Easy

How to compute a line integral on the TI89 using Calculus Made Easy and

in the Vector Calculus module?

Lets look at  question 6  in the image below:

line integral ti89 calculus made easy

line integral on ti89

 

Disregarding i and j notation, we instead enter the following under F2 2 LIne Integrals:

f=[2y,2x]

[x,y]   as variables used.

 

Next screen:

We have to create our own parametrization using the given points. Since we Line Integrals are independent of path (read more here http://tutorial.math.lamar.edu/Classes/CalcIII/FundThmLineIntegrals.aspx  ) we choose

[t,3*t] which get as from 0,0 to 2,6 doesn’t it?

t    is variable

[0,2] as t bounds . Double check that those t values get you from 0,0 to 2,6 using the above parametrization.

Voila , a computer algebra system verified the answer 24 .  The Fundamental Theorem of Calculus just never fails, and so does Calculus Made Easy!

 

I leave question 7 as a challenge for you . Reply here if you know how 😉

Mike
TI89guru

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One Response to “Line Integral computation on the TI89 using Calculus Made Easy”

  1. Marcus Says:

    Excellent thanks

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