How to compute a line integral on the TI89 using Calculus Made Easy and

in the Vector Calculus module?

Lets look at question 6 in the image below:

line integral on ti89

Disregarding i and j notation, we instead enter the following under F2 2 LIne Integrals:

f=[2y,2x]

[x,y] as variables used.

Next screen:

We have to create our own parametrization using the given points. Since we Line Integrals are independent of path (read more here http://tutorial.math.lamar.edu/Classes/CalcIII/FundThmLineIntegrals.aspx ) we choose

[t,3*t] which get as from 0,0 to 2,6 doesn’t it?

t is variable

[0,2] as t bounds . Double check that those t values get you from 0,0 to 2,6 using the above parametrization.

Voila , a computer algebra system verified the answer 24 . The Fundamental Theorem of Calculus just never fails, and so does Calculus Made Easy!

I leave question 7 as a challenge for you . Reply here if you know how 😉

Mike

TI89guru

*Related*

Excellent thanks

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