New Giveaway Puzzle at www.ti89.com Find a new Giveaway Puzzle at the top of www.TI89.com. The first person to solve this one qualifies for a free TI89 app. The solutions to the previous were clever and winners are now happy users of our TI89 apps. Share this:Click to share on Twitter (Opens in new window)Click to share on Facebook (Opens in new window)Click to share on Google+ (Opens in new window)Click to share on Pinterest (Opens in new window)Click to share on LinkedIn (Opens in new window)Click to print (Opens in new window)Click to email this to a friend (Opens in new window) Related Posted in Uncategorized on 24 June 2015 by ti89guru 5 Comments » ← TI89.com for mobile devices User comment (M.B.): Just want to thank you for the fabulous programs for Statistics → 5 Responses to New Giveaway Puzzle at www.ti89.com On July 11, 2015 at 8:10 PM, Gary Hamilton said: Hey guys bumping on the highest integer with 3 digits. We start to get really big numbers. Wrote a little code and still ran out of digits, Google give us 1.9662705e+77 that is rather large. Using Octave we get very similar at http://octave-online.net/ octave:1> 9^9^9 ans = 1.9663e+77 9^9^9 = 387420489^9 = 1.9662705e+77 It get to be enough digits my head hurts. If you have a clean way to calculate I would enjoy seeing more than my TI89 can handle I believe but you guys do a little magic with calculators so may you can make it work. Looks like summer is slowing you guys down. Respond to this Permalink On July 11, 2015 at 8:17 PM, Gary Hamilton said: Reading through this I may still need to work on this since it looks like my answer is still wrong because in truth it should be 9^387420489 I guess summer is getting to me. Back to Octave, obviously I have nothing to do on a Saturday night. Respond to this Permalink On July 11, 2015 at 8:55 PM, Gary Hamilton said: octave:27> 9^387420489 ans = Inf octave:39> 10^(0.631570358743543095) * 10^369693099 ans = Inf running over to WolframAlpha.com seem like I was wrong originally and they are a little more precise but as close as they will give for free is below which is way more accurate than I can prove. 9^387420489=4.281247731757470480369871159305635213390554822414435 * 10^369693099 Which is way more accurate than I can prove is there a longhand version that some can show with logs? I can probably search for it as well. Trying to use tools and hard head first. But beyond my capabilities to do long hand. Respond to this Permalink On August 17, 2015 at 5:40 AM, Thomas said: If you don’t have operators it is 999, if you do have operators then it is as big as the operator can become. For example if you make the operators 9!^9!^9! then it will be even bigger than the above answer but you can include even more operators to increase it more like ((((((((((999!)!)!)!)!)!)!)!)!)!) making it become extremely high but you could even create your own operator and do whatever you want with that ex: %* will make any 3 numbers turn into infinity. So then the answer would be %*999. Respond to this Permalink On August 22, 2015 at 9:32 AM, ti89guru said: Hi T Man very thorough solutions, however the free app was already claimed by the first respondent. Stay tuned, new challenges are coming up soon. Respond to this Permalink Cancel comment response Leave a Reply Cancel reply Your email address will not be published. Required fields are marked *CommentYou may use these HTML tags and attributes: <a href="" title=""> <abbr title=""> <acronym title=""> <b> <blockquote cite=""> <cite> <code> <del datetime=""> <em> <i> <q cite=""> <s> <strike> <strong> Name * Email * Website Save my name, email, and website in this browser for the next time I comment. Notify me of follow-up comments by email. Notify me of new posts by email.